(x+1)/(x+4)=(2x-1)/(x+6)
cross multiply the numbers
(x+1)(x+6) = (x+4)(2x-1)
unfoil the problem by multiplying every number from the first parenthesis by the numbers inside the second parenthesis
you should end up with
`x^2 +7x + 6 = 2x^2 + 7x - 4 `
Add the opposite of each number to combine like terms
x^2 +7x + 6 = 2x^2 + 7x - 4
+4 +4
x^2 +7x + 10 = 2x^2 + 7x
-7x -7x
x^2 + 10 = 2x^2
-x^2 -x^2
`10=x^2 `
find the square root
`sqrt(10) =sqrt(x^2)`
`x= +-sqrt(10)`
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