I am having so much trouble on this! "the length of a rectangle is 6 more than twice the width. Find the dimensions of the rectangle if the area is...

Here's another way to solve it.  Since you know the area is 56, and that the area is l x w, you can easily come up with a list of all the possible combinations that involve at least one side being a whole number.

56 x 1

28 x 2

18.66 x 3

14 x 4

11.2 x 5

9.33 x 6

7 x 8

The next would be 8 x 7, so you may as well stop.

Now see if any of these fit the formula of one number being equal to 2(the number) + 6.

56 x 1 -- 2 x 1 = 2, which is far more than 6 away from 56.

The same can be said of 28 x 2.

18.66 x 3 is closer.  However, 3 x 2 = 6, and 18.66 is more than 6 away from that.

14 x 4 is perfect!!  4 x 2 = 8, and 8 + 6 = 14.

Just to be safe, check the next to see if it's less than 6 away -- yes!  5 x 2 = 10, which is less than 6 away from 11.2.

So, you can safely say that W = 4 and L = 14.