To solve the equation sinx=1+cos^2x, we use the trigonometrical identiy sin^2+cos^2=1
From the above identity, cos^2x =1-sin^2x.Replacing this fact in the given equation we get:
sinx=1+(1-sin^2x). Rearrange this as a quadratic in sinx we get,
sin^2x+sinx-2=0=>{sinx+(1/2)}^2-(1/2)^2-2 =0=>
sinx+1/2 =sqrt(2.25) =+1.5 or -1.5
sinx=1.5-0.5 =1 or sinx =-1.5-0.5=-2.0 is not feasible, as sinx is always obeying the inequality, -1<=sinx<=1.
Thus sinx =1 gives x=Pi/2 is the only practical solution or x=Pi/2+2nPi is the general solution.
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